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SAT数学练习题内容二

2019-10-09 18:13:49来源：网络

　　为了帮助大家高效备考SAT，新东方在线SAT频道为大家带来SAT数学练习题内容二，希望对大家SAT备考有所帮助。更多精彩尽请关注新东方在线SAT频道!

　　答案：

　　1.Correct Answer: D

　　Explanation:

　　You can solve this by back solving – substitute the answer choices in the expression and see which gives the greatest value.sat

　　A (-1 + 2) / (-1-2) = -2 / 2 = -1;

　　B (0 + 2) / (0-2) = 2/ -2 = -1;

　　C (1 + 2) / (1-2) = 3/-1 = -3;

　　D (3 + 2) / (3-2) = 5/1 = 5;

　　E (4+ 2) / (4-2) = 6/2 = 3

　　If you had just chosen the largest value for x you would have been wrong. So although it looks a long method, it is actually quick and accurate since the numbers are really simple and you can do the math in your head.

　　2.Correct Answer: D

　　Explanation:

　　(Total area of square - sum of the areas of triangles ADE and DCF) will give the area of the quadrilateral 9 - (2 x ? x 3 x 1.5) = 4.5

　　3.Correct Answer: E

　　Explanation:

　　Remember that n could be positive negative or a fraction. Try out a few cases: In case I, if n is -1, then 2n is less than n. In case II, if n is a fraction such as ? then n2 will be less than n. In case III, if n is 2, then 2-n = 0, which is less than n. Therefore, none of the choices must be greater than n

　　4.Correct Answer: C

　　Explanation:

　　If after each bounce it reaches 2/5 of the previous height, then after the second bounce it will reach 2/5 x 125. After the third it will reach 2/5 x 2/5 x 125. After the fourth it will reach 2/5 x 2/5 x 2/5 x 125. This cancels down to 2 x 2 x 2 = 8

　　5.Correct Answer: A

　　Explanation:

　　The smallest value for n such that 5n is a square is 5. 75np can now be written as 75 x 5 x p. This gives prime factors.... 3 x 5 x 5 x 5 x p To make the expression a perfect cube, p will have to have factors 3 x 3 , and hence p =9 n + p = 5 + 9 = 14

　　以上就是关于“SAT数学练习题内容二”的内容，更多精彩内容，请关注SAT频道!

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