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SAT模拟考试题：SAT数学练习题(15)

2016-08-11 16:55:05来源：网络

　　SAT模拟考试SAT数学练习题(15)：本文是sat数学模拟题。新东方在线SAT频道为大家整理了SAT模拟考试题，供考生们参考，以下是详细内容。

　　Question #1: In the x,y plane, which of the following statements are true?

　　I. Line y + x = 5 is perpendicular to line y - x = 5.

　　II. Lines y + x = 5 and y - x = 5 intersect each other on the y axis.

　　III. Lines y + x = 5 and y - x = 5 intersect each other on the x axis.

　　(a) I and III are both true.

　　(b) I is the only true statement.

　　(c) II is the only true statement.

　　(d) I and II are both true.

　　Answer: y + x = 5 can be written as y = -x + 5. The slope of this equation is m1 = -1.

　　y - x = 5 can be written as y = x + 5. The slope of this equation is m2 = 1.

　　m2 = -1/m1 so the 2 lines are perpendicular.

　　We also need to find where the 2 lines intersect. If we add the 2 equations, 2·y = 10, y = 5.

　　From the first equation, x = 5 - y = 5 - 5 = 0. In conclusion the lines intersect at (0, 5) and this point is on the y axis.

　　In conclusion I and II statements are correct.

　　Question #2: If a is an integer chosen randomly from the set {3, 5, 6, 9} and b is an integer chosen randomly from the set {2, 3, 4}, what is the probability that a/b is an integer?

　　(a) .125

　　(b) .250

　　(c) .333

　　(d) .5

　　(e) .55

　　Answer: We have 4 possible integers for a and 3 for b, so the number of possible combinations for a/b is 4 · 3 = 12.

　　a/b is an integer only for 4 combinations:

　　1. a = 3 and b = 3

　　2. a = 6 and b = 2

　　3. a = 6 and b = 3

　　4. a = 9 and b = 3

　　The probability that a/b is an integer is 4/12 = 1/3 = .333.

　　Question #3: What is the value of integer a, if x = 2 is a solution of the equation √(a + x) = 2·x?

　　(a) a = 10

　　(b) a = 12

　　(c) a = 14

　　(d) a = 16

　　(e) a = 18

　　Answer: If we square the equation we get a + x = 4·x2

　　By replacing x with 2, a + 2 = 4·22, so a + 2 = 16.

　　In conclusion, a = 14.

　　Question #4: What is the value of (3x + 1 - 3x) / (3x - 3x - 1)?

　　(a) 6

　　(b) 3x

　　(c) 3x + 1

　　(d) 3x - 1

　　(e) 3

　　Answer: The numerator of the fraction is: 3x + 1 - 3x = 3x·(3 - 1) = 2 · 3x

　　The denominator of the fraction is: 3x - 3x - 1 = 3x - 1·(3 - 1) = 2 · 3x - 1

　　We can write the fraction as (2 · 3x) / (2 · 3x - 1) = 3x / 3x - 1 = 3

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