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SAT模拟考试题:SAT数学练习题(15)

2016-08-11 16:55:05来源:网络

  Answer: We need to compare x2 + 1 with x + 1. This results in a comparison between x2 and x.

  For some x, x2 will be greater than x, e.g. for x = 2. For others, e.g. x = 1/2, x2 will be lower so the relationship cannot be determined from the information given.

  Question #9:

  2·m - n = 4

  m + 2·n = 12

  Column AColumn B

  (m + n)261

  (a) The quantity in Column A is greater then the quantity in Column B.

  (b) The quantity in Column B is greater then the quantity in Column A.

  (c) The two quantities are equal.

  (d) The relationship cannot be determined from the information given.

  Answer: From the first equation, n = 2·m - 4. Then, the first equation will be m + 2·(2·m - 4) = 12

  m + 4·m - 8 = 12 so 5·m = 20 and m = 4

  From the first equation, n = 2·m - 4 = 2·4 - 4 = 4

  Column A expression will be (m + n)2 = (4 + 4)2 = (8)2 = 64

  The quantity in Column A is greater than the quantity in Column B.

  Question #7: If a and b are positive integers and a·b = 200, which of the following can be the sum a + b?

  (a) 40

  (b) 46

  (c) 33

  (d) 55

  (e) 50

  Answer: 200 = 2·2·2·5·5.

  If a and b are positive integers, the 2 numbers and their sum can be:

  2 + 100 = 102

  4 + 50 = 54

  5 + 40 = 45

  8 + 25 = 33

  10 + 20 = 30

  (c) is the correct answer.

  更多SAT模拟考试题及备考资料敬请查看SAT真题栏目。


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本文关键字: SAT模拟考试 SAT数学

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