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4道SAT数学选择题精选练习

2013-10-30 18:25:00来源:网络

  参考答案及解析:

  1.The correct answer is C

  Explanation

  Letstand for the number of students who belong to both clubs. Themembers of the math club can be broken down into two groups: those who are in both clubs (there arestudents in this category) and those who are in the math club only (there arestudents in this category).

  Themembers of the chess club can also be broken down into two groups:students who are in both clubs andstudents who are in the chess club only.

  Since a total ofstudents belong to only one of the two clubs, you know that. Solving this equation gives, sostudents belong to both clubs.

  2.The correct answer is A

  Explanation

  If, then by the commutative property of multiplication,. Multiplying each side of the latter equation bygives, so.

  3.The correct answer is D

  Explanation

  Ifand, and if, then rewritingasgives. It follows that, and so. This last equation is equivalent to.

  4.The correct answer is D

  Explanation

  Sinceand, it follows thatand, therefore,. So.

  以上就是关于4道SAT考试数学选择题练习题及其答案和解析,非常详细。同学们在备考阶段,一定要加强习题的练习以及题意的理解,争取SAT数学满分。

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