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SAT模拟考试题:SAT数学练习题(13)

2016-08-11 16:52:25来源:网络

  Question #4: A vehicle runs from town A to town B at a speed of 20 miles/hour while another vehicle runs from town B to town A at a speed of 60 miles/hour. Both vehicles start their trips at the same time and the distance between towns is 100 miles. How long does it take from the time they start running to the moment they are at the same point on the road?

  (a) 1 hour

  (b) 1 hour and 15 minutes

  (c) 1 hour and 30 minutes

  (d) 1 hour and 45 minutes

  (e) 2 hours and 15 minutes

  100 miles = d1 + d2 This is equation #1.

  It take the same time for the 2 cars to meet: t = d1/(20 miles/hour) = d2/(60miles/hour). This is equation #2.

  We solve the system of 2 equations to find d1 and d2.

  From equation #2, 3·d1 = d2.

  Then 100 miles = d1 + d2 = 4·d1, so d1 = 25 miles and d2 = 75 miles.

  The answer is t = d1/20miles/hour = 25/20 = 5/4 = 1 hour and 15 minutes.

  Question #5: Given the list of integers: -2, 2, 0, 6, 8, 0, -5, 9, 10, 4, which of the following statements is true?

  (a) mode < median < average

  (b) median < mode < average

  (c) median < average < mode

  (d) mode = median < average

  (e) average < median < mode

  Answer: We need to rearrange the list of integers in order: -5, -2, 0, 0, 2, 4, 6, 8, 9, 10. The average will be the sum of all integers divided by the number of integers, 32/10 = 3.2

  The median will be the mean of the 2 middle numbers, 2 and 4, so the median is 3.

  The mode is 0, as 0 occurs the most in the list.

  The correct answer is mode < median < average.

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本文关键字: SAT模拟考试 SAT数学

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